ch33-p054 - 54. (a) From n1sinθ1 = n2sinθ2 and n2sinθ2 =...

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Unformatted text preview: 54. (a) From n1sinθ1 = n2sinθ2 and n2sinθ2 = n3sinθ3, we find n1sinθ1 = n3sinθ3. This has a simple implication: that θ1 =θ3 when n1 = n3. Since we are given θ1 = 40º in Fig. 3356(a) then we look for a point in Fig. 33-56(b) where θ3 = 40º. This seems to occur at n3 = 1.6, so we infer that n1 = 1.6. (b) Our first step in our solution to part (a) shows that information concerning n2 disappears (cancels) in the manipulation. Thus, we cannot tell; we need more information. (c) From 1.6sin70° = 2.4sinθ3 we obtain θ3 = 39°. ...
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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