tangent of the angle of incidence. The diameter of the circle in question is given by d= 2htan θc. For water n= 1.33, so Eq. 33-47 gives sin c= 1/1.33, or c= 48.75°. Thus, 2 tan2(2.00 m)(tan 48.75 )4.56 m.cdh==°=(b) The diameter dof the circle will increase if the fish descends (increasing h). 60. (a) Reference to Fig. 33-24 may help in the visualization of why there appears to be a
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.