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tangent of the angle of incidence. The diameter of the circle in question is given by
d
=
2
h
tan
θ
c
. For water
n
= 1.33, so Eq. 3347 gives sin
c
= 1/1.33, or
c
= 48.75°. Thus,
2 tan
2(2.00 m)(tan 48.75 )
4.56 m.
c
dh
==
°
=
(b) The diameter
d
of the circle will increase if the fish descends (increasing
h
).
60. (a) Reference to Fig. 3324 may help in the visualization of why there appears to be a
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Light

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