ch33-p062 - 62. (a) The condition (in Eq. 33-44) required...

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62. (a) The condition (in Eq. 33-44) required in the critical angle calculation is θ 3 = 90°. Thus (with 2 = c , which we don’t compute here), nn n 11 2 2 33 sin = = leads to 1 = = sin –1 n 3 / n 1 = 54.3°. (b) Yes. Reducing leads to a reduction of 2 so that it becomes less than the critical angle; therefore, there will be some transmission of light into material 3. (c) We note that the complement of the angle of refraction (in material 2) is the critical
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