70. Since the layers are parallel, the angle of refraction regarding the first surface is the same as the angle of incidence regarding the second surface (as is suggested by the notation in Fig. 33-66). We recall that as part of the derivation of Eq. 33-49 (Brewster’s angle), the refracted angle is the complement of the incident angle: θ21190==°−().cWe apply Eq. 33-49 to both refractions, setting up a product:
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.