tdc==××=×−150 10300 10500 10384mm/ss... (b) At full moon, the Moon and Sun are on opposite sides of Earth, so the distance traveled by the light is d= (1.5 ×108km) + 2 (3.8 ×105km) = 1.51 ×108km = 1.51 ×1011m. The time taken by light to travel this distance is 1181.51 10 m500 s8.4 min.3.00 10 m/sdtc×==×(c) We take dto be 2(1.3 ×109km) = 2.6 ×1012m. Then, tdc××=26 1087 1024123...m3.00 10 m / ss h.8(d) We take dto be 6500 ly and the speed of light to be 1.00 ly/y. Then,
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.