(b) Figure 33-5 may help in visualizing this. The direction of propagation (along the yaxis) is perpendicular to GB(presumably along the xaxis, since the problem gives Bxand no other component) and both are perpendicular to GE(which determines the axis of polarization). Thus, the wave is z-polarized. (c) Since the magnetic field amplitude is Bm= 4.00 µT, then (by Eq. 33-5) Em= 1199 V/m 31.20 10 V/m≈×. Dividing by 2yields Erms= 848 V/m. Then, Eq. 33-26 gives IIcE==×03191 10rms22W/m..(d) Since kc =
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.