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Unformatted text preview: 10. (a) We note that ray 1 travels an extra distance 4L more than ray 2. To get the least
possible L which will result in destructive interference, we set this extra distance equal to
half of a wavelength:
λ 420.0 nm
⇒ L= =
= 52.50 nm .
3 (b) The next case occurs when that extra distance is set equal to 2 λ. The result is
L= 3λ 3(420.0 nm)
= 157.5 nm .
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- Spring '08