ch35-p010 - 10. (a) We note that ray 1 travels an extra...

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Unformatted text preview: 10. (a) We note that ray 1 travels an extra distance 4L more than ray 2. To get the least possible L which will result in destructive interference, we set this extra distance equal to half of a wavelength: λ λ 420.0 nm 4L = ⇒ L= = = 52.50 nm . 2 8 8 3 (b) The next case occurs when that extra distance is set equal to 2 λ. The result is L= 3λ 3(420.0 nm) = = 157.5 nm . 8 8 ...
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