ch35-p022 - d d sin = m ⇒ d =(4(450 nm/sin(90° = 1800...

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(b) The slit separation d needs to be decreased. (c) In this case, the 400 nm wavelength in the m = 4 diffraction is to occur at 90°. Thus d new sin θ = m λ d new = (4)(400 nm)/sin(90°) = 1600 nm . This represents a change of | d | = d d new = 200 nm = 0.20 μm. 22. (a) We use Eq. 35-14 to find
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Unformatted text preview: d : d sin = m λ ⇒ d = (4)(450 nm)/sin(90°) = 1800 nm . For the third order spectrum, the wavelength that corresponds to = 90° is λ = d sin(90°)/3 = 600 nm . Any wavelength greater than this will not be seen. Thus, 600 nm < ≤ 700 nm are absent....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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