Unformatted text preview: d : d sin = m Î» â‡’ d = (4)(450 nm)/sin(90Â°) = 1800 nm . For the third order spectrum, the wavelength that corresponds to = 90Â° is Î» = d sin(90Â°)/3 = 600 nm . Any wavelength greater than this will not be seen. Thus, 600 nm < â‰¤ 700 nm are absent....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
- Spring '08