ch35-p040 - 40 The situation is analogous to that treated...

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0, 280nm, 560nm, 840nm,1120nm, L = for the first several m values. And the equation shown above (equivalent to Eq. 35-36) gives, with λ = 600 nm, L = 120nm,360nm,600nm,840nm,1080nm, for the first several m values. The lowest number these lists have in common is 840 nm. L = 40. The situation is analogous to that treated in Sample Problem 35-6, in the sense that the incident light is in a low index medium, the thin film of acetone has somewhat higher n = n 2 , and the last layer (the glass plate) has the highest refractive index. To see very little or no reflection, according to the Sample Problem, the condition
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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