ch35-p047 - 47. In this setup, we have n2 > n1 and...

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Unformatted text preview: 47. In this setup, we have n2 > n1 and n2 < n3 , and the condition for destructive interference is 1⎞ λ ⎛ 2L = ⎜ m + ⎟ 2 ⎠ n2 ⎝ ⇒ λ= 4 Ln2 , 2m + 1 m = 0,1, 2,... Thus, ⎧4 Ln2 = 4(210 nm)(1.46) = 1226 nm (m = 0) . ⎩4 Ln2 / 3 = 4(210 nm)(1.46) / 3 = 409 nm (m = 1) λ=⎨ For the wavelength to be in the visible range, we choose m=1 with λ = 409 nm. ...
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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