54. For constructive interference (which is obtained for
λ
= 600 nm) in this circumstance,
we require
2
22
n
kk
L
n
λ
==
where
k
= some positive odd
integer
and
n
is the index of refraction of the thin film.
Rearranging and plugging in
L
= 272.7 nm and the wavelength value, this gives
(600 nm)
0.55
4
4(272.7 nm)
1.818
k
nk
L
=
=
.
Since we expect
n
> 1, then
k
= 1 is ruled out.
However,
k
= 3 seems reasonable, since it
leads to
n
= 1.65, which is close to the “typical” values found in Table 341.
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

Click to edit the document details