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54. For constructive interference (which is obtained for
λ
= 600 nm) in this circumstance,
we require
2
22
n
kk
L
n
λ
==
where
k
= some positive odd
integer
and
n
is the index of refraction of the thin film.
Rearranging and plugging in
L
= 272.7 nm and the wavelength value, this gives
(600 nm)
0.55
4
4(272.7 nm)
1.818
k
nk
L
=
=
.
Since we expect
n
> 1, then
k
= 1 is ruled out.
However,
k
= 3 seems reasonable, since it
leads to
n
= 1.65, which is close to the “typical” values found in Table 341.
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 Spring '08
 Any
 Physics

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