ch35-p066 - 66. In this setup, we have n2 > n1 and n2...

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2 2 4 1 2 , 0,1,2,. .. 22 1 Ln Lm m nm λ ⎛⎞ =+ = = ⎜⎟ + ⎝⎠ Thus, we have 2 2 4 4(210 nm)(1.46) 1226 nm ( 0) 4 /3 4(210 nm)(1.46)/3 409 nm ( 1) Ln m Ln m == = = = . For the wavelength to be in the visible range, we choose m =1 with
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