ch35-p081 - 81. Let 1 be the phase difference of the waves...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
81. Let φ 1 be the phase difference of the waves in the two arms when the tube has air in it, and let 2 be the phase difference when the tube is evacuated. These are different because the wavelength in air is different from the wavelength in vacuum. If λ is the wavelength in vacuum, then the wavelength in air is λ / n , where n is the index of refraction of air. This means φφ 12 2 2241 −= L N M O Q P = L n nL π λ π λ π λ bg where L is the length of the tube. The factor 2 arises because the light traverses the tube
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online