ch35-p085 - d = 50.0 nm. (b) The above requirement becomes...

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85. (a) The path length difference between Rays 1 and 2 is 7 d – 2 d = 5 d . For this to correspond to a half-wavelength requires 5 d = λ /2, so that
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Unformatted text preview: d = 50.0 nm. (b) The above requirement becomes 5 d = /2 n in the presence of the solution, with n = 1.38. Therefore, d = 36.2 nm....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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