ch35-p088 - S 2 is 1360 nm ( 1360/400 = 3.4 ) from P 2 ....

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88. (a) Since P 1 is equidistant from S 1 and S 2 we conclude the sources are not in phase with each other. Their phase difference is φ source = 0.60 π rad, which may be expressed in terms of “wavelengths” (thinking of the λ 2 π correspondence in discussing a full cycle) as source = (0.60 π / 2π ) λ = 0.3 λ (with S 2 “leading” as the problem states). Now S 1 is closer to P 2 than S 2 is. Source S 1 is 80 nm ( 80/400 λ = 0.2 λ ) from P 2 while source
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Unformatted text preview: S 2 is 1360 nm ( 1360/400 = 3.4 ) from P 2 . Here we find a difference of path = 3.2 (with S 1 leading since it is closer). Thus, the net difference is net = path source = 2.90 , or 2.90 wavelengths. (b) A whole number (like 3 wavelengths) would mean fully constructive, so our result is of the following nature: intermediate, but close to fully constructive....
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