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Unformatted text preview: 103. Let the position of the mirror measured from the point at which d1 = d2 be x. We
assume the beamsplitting mechanism is such that the two waves interfere constructively
for x = 0 (with some beamsplitters, this would not be the case). We can adapt Eq. 3523
to this situation by incorporating a factor of 2 (since the interferometer utilizes directly
reflected light in contrast to the doubleslit experiment) and eliminating the sin θ factor.
Thus, the phase difference between the two light paths is ∆φ = 2(2πx/λ) = 4πx/λ. Then
from Eq. 3522 (writing 4I0 as Im) we find
I = I m cos2 FG ∆φ IJ = I
H2K m cos2 FG 2πx IJ .
HλK ...
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 Spring '08
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