ch35-p104 - 104. (a) Since n2 > n3, this case has no...

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λ= ′ + = ′ + 2 12 525 2 nL mm nm , where m' = 0, 1, 2, 3, …. In the visible light range m' = 1 and λ = 350 nm. This corresponds to the blue-violet light. 104. (a) Since n 2 > n 3 , this case has no π -phase shift, and the condition for constructive interference is m λ = 2 Ln 2 . We solve for L : L m n m m == = λ 2 2 525 2155 169 b g b g b g . . For the minimum value of L , let m = 1 to obtain L min = 169 nm. (b) The light of wavelength λ (other than 525 nm) that would also be preferentially transmitted satisfies m' λ = 2 n 2 L , or = = 2 2 155 169
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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