ch35-p122 - 122. (a) To get to the detector, the wave from...

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(j) When 1.500 ( 3/ 2) Lm λ ∆= = , the interference is fully destructive. (k) Using the formula obtained in part (a), we have x = 2.29 µ m for 3/2 m = . (l) When 2.00 ( 2) = , the interference is fully constructive. (m) Using the formula obtained in part (a), we have 1.50 m x = for m = 2. (n) When 2.500 ( 5/ 2) = , the interference is fully destructive. (o) Using the formula obtained in part (a), we have x = 0.975 m for 5/2 m = . 122. (a) To get to the detector, the wave from S 1 travels a distance x and the wave from S 2 travels a distance dx 22 + . The phase difference (in terms of wavelengths) between the two waves is 0,1, 2, dxx m m +− = λ = where we are requiring constructive interference. The solution is x dm m = 2 2 λ λ . We see that setting m = 0 in this expression produces x = ; hence, the phase difference between the waves when P is very far away is 0. (b) The result of part (a) implies that the waves constructively interfere at P . (c) As is particularly evident from our results in part (d), the phase difference increases as
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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