ch36-p002 - 2. (a) = sin1 (1.50 cm/2.00 m) = 0.430. (b) For...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
2. (a) θ = sin –1 (1.50 cm/2.00 m) = 0.430°. (b) For the m th diffraction minimum a sin = m λ . We solve for the slit width:
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online