ch36-p002 - 2(a = sin1(1.50 cm/2.00 m = 0.430(b For the mth...

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2. (a) θ = sin –1 (1.50 cm/2.00 m) = 0.430°. (b) For the m th diffraction minimum a sin = m λ . We solve for the slit width:
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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