This preview shows page 1. Sign up to view the full content.
9. The condition for a minimum of intensity in a singleslit diffraction pattern is
a
sin
θ
=
m
λ
, where
a
is the slit width,
λ
is the wavelength, and
m
is an integer. To find the angular
position of the first minimum to one side of the central maximum, we set
m
= 1:
1
11
9
3
4
589 10
100 10
589 10
=
F
H
G
I
K
J
=
×
×
F
H
G
I
K
J
=×
−−
−
−
−
sin
.
..
λ
a
m
m
rad
If
D
is the distance from the slit to the screen, the distance on the screen from the center
of the pattern to the minimum is
yD
43
300
589 10
1767 10
==
×
=
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Diffraction

Click to edit the document details