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∆
θθ
==
F
H
G
I
K
J
−
22
0 442
1
sin
.
.
λ
a
(d) For
a
/
λ
= 1.0,
( )
1
2sin
0.442 1.0
0.916rad
52.5
θ
−
∆=
=
=
°
.
(e) For
a
/
λ
= 5.0,
( )
1
0.442 5.0
0.177rad
10.1
−
=
=
°
.
(f) For
a
/
λ
= 10,
∆
=
°
−
2
0 442 10
0 0884
506
1
.
.
.
.
bg
rad
17. (a) The intensity for a singleslit diffraction pattern is given by
II
m
=
2
2
α
where
= (
π
a
/
λ
) sin
,
a
is the slit width and
λ
is the wavelength. The angle
is
measured from the forward direction. We require
I = I
m
/2, so
.
1
2
αα
=
(b) We evaluate sin
2
and
2
2 for
= 1.39 rad and compare the results. To be sure
that 1.39 rad is closer to the correct value for
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 Spring '08
 Any
 Physics, Diffraction

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