This distance is greater than the diameter of Mars; therefore, one part of the planet’s surface cannot be resolved from another part. (b) Now d= 5.1 m and D=××=×=−122 8 0 10550 105111 10111094...mmmmkmchch25. (a) We use the Rayleigh criteria. If Lis the distance from the observer to the objects, then the smallest separation
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