λ=cf=××=×−300 10220 10136 10893...msHzm Thus, θ=FHGIKJ=××FHGIKJ−−−−−sin..11323122122 136 10550 10302 10λdmmradchThe angular width of the central maximum is twice this, or 6.04 ×10–3rad (0.346°). (b) Now λ= 1.6 cm and d= 2.3 m, so =×FHGIKJ−−−.123122 16 102385 10mmradchThe angular width of the central maximum is 1.7 ×10–2rad (or 0.97°). 29. (a) The first minimum in the diffraction pattern is at an angular position
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.