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which suggests that the angle takes us to a point between the sixth minimum (which
would have
m
= 6.5) and the seventh maximum (which corresponds to
m
= 7).
(c) Similarly, consider Eq. 363 with “continuously variable”
m
(of course,
m
should be
an integer for diffraction minima, but for the moment we will solve for it as if it could be
any real number):
( )
12.0 m sin9.93
sin
3.4
0.600 m
a
m
µ
θ
°
==
≈
λ
which suggests that the angle takes us to a point between the third diffraction minimum
(
m
= 3) and the fourth one (
m
= 4).
The maxima (in the smaller peaks of the diffraction
pattern) are not exactly midway between the minima; their location would make use of
mathematics not covered in the prerequisites of the usual sophomorelevel physics course.
43. We will make use of arctangents and sines in our solution, even though they can be
“shortcut” somewhat since the angles are [almost] small enough to justify the use of the
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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