47. The distance between adjacent rulings is d= 20.0 mm/6000 = 0.00333 mm = 3.33 µm. (a) Let()sin0, 1, 2,dmmθ=λ =±±…. Since |m|λ/d> 1 for |m| ≥6, the largest value of corresponds to | m| = 5, which yields 115(0.589 m)sin||/sin62.13.33 mmd−−⎛⎞=λ==°⎜⎟⎝⎠(b) The second largest value of corresponds to |m| = 4, which yields
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