ch36-p050 - 50. (a) For the maximum with the greatest value...

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50. (a) For the maximum with the greatest value of m (= M ) we have M λ = a sin θ < d , so M < d / λ = 900 nm/600 nm = 1.5, or M = 1. Thus three maxima can be seen, with m = 0, ±1. (b) From Eq. 36-28, we obtain
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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