ch36-p053 - 53. The angular positions of the first-order...

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d = −+ = −° + ° ° == × λλ θ λ 21 2 1 2 2 22 2 4 680 430 20 430 20 20 914 914 10 cos sin sin cos sin . ∆∆ bg b g b g b g b g nm nm mm. There are 1/ d = 1/(9.14 × 10 –4 mm) = 1.09 × 10 3 rulings per mm. 53. The angular positions of the first-order diffraction lines are given by d sin = λ . Let λ 1 be the shorter wavelength (430 nm) and be the angular position of the line associated with it. Let λ 2 be the longer wavelength (680 nm), and let + be the angular position of the line associated with it. Here
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