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d
=
−+
=
−°
+
°
°
==
×
−
λλ
θ
λ
21
2
1
2
2
22
2
4
680
430
20
430
20
20
914
914 10
cos
sin
sin
cos
sin
.
∆∆
∆
bg
b
g
b
g
b
g
b
g
nm
nm
mm.
There are 1/
d
= 1/(9.14
×
10
–4
mm) = 1.09 × 10
3
rulings per mm.
53. The angular positions of the firstorder diffraction lines are given by
d
sin
=
λ
. Let
λ
1
be the shorter wavelength (430 nm) and
be the angular position of the line associated
with it. Let
λ
2
be the longer wavelength (680 nm), and let
+
∆
be the angular position
of the line associated with it. Here
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 Spring '08
 Any
 Physics, Diffraction

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