( )( )61.0 10 nm/350 0.1644sin470nm.dmθ×===λλλSince for white light λ> 400 nm, the only integer mallowed here is m= 1. Thus, at one edge of the hole, λ= 470 nm. This is the shortest wavelength of the light that passes through the hole. (b) At the other edge, we have tan θ '= 6.0 cm/30 cm, which gives '= 11.31°. This leads to 61.0 10 nmsinsin(11.31 )560 nm.350dλθ⎛⎞×′′
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.