( )( )
6
1.0 10 nm/350 0.1644
sin
470nm
.
d
m
θ
×
==
=
λλ
λ
Since for white light
λ
> 400 nm, the only integer
m
allowed here is
m
= 1. Thus, at
one edge of the hole,
λ
= 470 nm. This is the shortest wavelength of the light that passes
through the hole.
(b) At the other edge, we have tan
θ
'
= 6.0 cm/30 cm, which gives
'
= 11.31°. This
leads to
6
1.0 10 nm
sin
sin(11.31 )
560 nm.
350
d
λθ
⎛⎞
×
′′
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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