ch36-p055 - 55 At the point on the screen where we find the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
( )( ) 6 1.0 10 nm/350 0.1644 sin 470nm . d m θ × == = λλ λ Since for white light λ > 400 nm, the only integer m allowed here is m = 1. Thus, at one edge of the hole, λ = 470 nm. This is the shortest wavelength of the light that passes through the hole. (b) At the other edge, we have tan θ ' = 6.0 cm/30 cm, which gives ' = 11.31°. This leads to 6 1.0 10 nm sin sin(11.31 ) 560 nm. 350 d λθ ⎛⎞ × ′′
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online