ch36-p060 - 60(a From R = = Nm we find N= b g 415.496 nm...

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60. (a) From RN m == λ∆λ we find N m + = λ λ 415496 415487 2 2 41596 23100 .. . nm bg b g (b) We note that d = (4.0 × 10 7 nm)/23100 = 1732 nm. The maxima are found at
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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