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Unformatted text preview: 69. (a) For the first beam 2d sin θ1 = λA and for the second one 2d sin θ2 = 3λB. The
values of d and λA can then be determined:
d= c b g 3 97 pm
3λ B
=
= 17 × 102 pm.
.
2 sin θ 2 2 sin 60° hb g .
.
(b) λ A = 2d sin θ 1 = 2 17 × 102 pm sin 23° = 13 × 102 pm. ...
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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