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Unformatted text preview: 82. Although the angles in this problem are not particularly big (so that the small angle
approximation could be used with little error), we show the solution appropriate for large
as well as small angles (that is, we do not use the small angle approximation here). Eq.
363 gives
mλ = a sinθ ⇒ θ = sin–1(mλ/a) = sin–1[2(0.42 µm)/(5.1 µm)] = 9.48°. The geometry of Figure 3510(a) is a useful reference (even though it shows a double slit
instead of the single slit that we are concerned with here). We see in that figure the
relation between y, D and θ:
y = D tan θ = (3.2 m) tan(9.48°) = 0.534 m . ...
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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