ch36-p087 - 87. We solve Eq. 36-25 for d: d= m 2(600 109 m)...

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87. We solve Eq. 36-25 for d : 9 64 2(600 10 m) 2.203 10 m 2.203 10 cm sin sin33 m d λ θ −− × == ° which is typically expressed in reciprocal form as the “number of lines per centimeter”
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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