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99. (a) Use of Eq. 3625 for the limitwavelengths (
λ
1
= 700 nm and
λ
2
= 550 nm) leads
to the condition
mm
12
λ
λ
≥
for
m
1
+ 1 =
m
2
(the low end of a highorder spectrum is what is overlapping with the
high end of the nextlowerorder spectrum). Assuming equality in the above equation, we
can solve for “
m
1
” (realizing it might not be an integer) and obtain
m
1
≈
4 where we have
rounded
up
. It is the fourth order spectrum that is the lowestorder spectrum to overlap
with the next higher spectrum.
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 Spring '08
 Any
 Physics

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