(b) Let the third-order maximum for λ2= 600 nm be the first minimum for the single-slit diffraction profile. This requires that dsin θ= 3λ2= asin , or a = d/3 = 2400 nm/3 = 800 nm = 0.80 µm. (c) Letting sin = mmaxλ2/d≤1, we obtain mdmax.≤==λ224008003nmSince the third order is missing the only maxima present are the ones with m= 0, 1 and 2. Thus, the largest order of maxima produced by the grating is
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.