ch36-p103 - 103. (a) We require that sin = m1,2/d sin 30,...

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(b) Let the third-order maximum for λ 2 = 600 nm be the first minimum for the single-slit diffraction profile. This requires that d sin θ = 3 λ 2 = a sin , or a = d /3 = 2400 nm/3 = 800 nm = 0.80 µ m. (c) Letting sin = m max λ 2 / d 1, we obtain m d max . ≤= = λ 2 2400 800 3 nm Since the third order is missing the only maxima present are the ones with m = 0, 1 and 2. Thus, the largest order of maxima produced by the grating is
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