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Unformatted text preview: 104. For λ = 0.10 nm, we have scattering for order m, and for λ' = 0.075 nm, we have
scattering for order m'. From Eq. 36-34, we see that we must require
mλ = m' λ ' which suggests (looking for the smallest integer solutions) that m = 3 and m' = 4.
Returning with this result and with d = 0.25 nm to Eq. 36-34, we obtain θ = sin −1 mλ
= 37° .
2d Studying Figure 36-30, we conclude that the angle between incident and scattered beams
is 180° – 2θ = 106°. ...
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
- Spring '08