109. One strategy is to divide Eq. 36-25 by Eq. 36-3, assuming the same angle (a point we’ll come back to, later) and the same light wavelength for both: sin''sinmmddaaλθλθ===. We recall that dis measured from middle of transparent strip to the middle of the next transparent strip, which in this particular setup means d = 2a. Thus,m/m′= 2, or m = 2m. Now we interpret our result. First, the division of the equations is not valid when m= 0 (which corresponds to = 0), so our remarks do not apply to the m= 0 maximum.
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.