ch36-p109 - 109. One strategy is to divide Eq. 36-25 by Eq....

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109. One strategy is to divide Eq. 36-25 by Eq. 36-3, assuming the same angle (a point we’ll come back to, later) and the same light wavelength for both: sin '' s i n mm d d a a λ θ λθ = == . We recall that d is measured from middle of transparent strip to the middle of the next transparent strip, which in this particular setup means d = 2 a. Thus, m/m = 2, or m = 2 m . Now we interpret our result. First, the division of the equations is not valid when m = 0 (which corresponds to = 0), so our remarks do not apply to the m = 0 maximum.
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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