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109. One strategy is to divide Eq. 3625 by Eq. 363, assuming the same angle (a point
we’ll come back to, later) and the same light wavelength for both:
sin
''
s
i
n
mm
d
d
a
a
λ
θ
λθ
=
==
.
We recall that
d
is measured from middle of transparent strip to the middle of the next
transparent strip, which in this particular setup means
d =
2
a.
Thus,
m/m
′
=
2, or
m
=
2
m
.
Now we interpret our result.
First, the division of the equations is not valid when
m
= 0
(which corresponds to
= 0), so our remarks do not apply to the
m
= 0 maximum.
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Light

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