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13. (a) Let
d
= 23000 ly = 23000
c
y, which would give the distance in meters if we
included a conversion factor for years
→
seconds. With
∆
t
0
= 30 y and
∆
t = d
/
v
(see Eq.
3710), we wish to solve for
v
from Eq. 377. Our first step is as follows:
0
22
23000 y
30 y
,
11
t
d
t
v
β
∆
∆= =
⇒
=
−−
at which point we can cancel the unit year and manipulate the equation to solve for the
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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