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22
11
7.09.
1
1 (0.99)
γ
β
==
=
−−
Thus,
∆
t
0
= (26.26 y)/(7.09) = 3.705 y.
15. (a) The speed of the traveler is
v
= 0.99
c
, which may be equivalently expressed as
0.99 ly/y. Let
d
be the distance traveled. Then, the time for the trip as measured in the
frame of Earth is
∆
t = d
/
v
= (26 ly)/(0.99 ly/y) = 26.26 y.
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 Spring '08
 Any
 Physics

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