ch37-p015 - 15. (a) The speed of the traveler is v = 0.99c,...

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22 11 7.09. 1 1 (0.99) γ β == = −− Thus, t 0 = (26.26 y)/(7.09) = 3.705 y. 15. (a) The speed of the traveler is v = 0.99 c , which may be equivalently expressed as 0.99 ly/y. Let d be the distance traveled. Then, the time for the trip as measured in the frame of Earth is t = d / v = (26 ly)/(0.99 ly/y) = 26.26 y.
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