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Similarly, let
t
b
be the time and
x
b
be the coordinate of the big flash, as measured in frame
S
. Then, the time of the big flash, as measured in frame
S'
, is
.
b
bb
x
tt
c
β
⎛⎞
′=γ
−
⎜⎟
⎝⎠
Subtracting the second Lorentz transformation equation from the first and recognizing
that
t
s
= t
b
(since the flashes are simultaneous in
S
), we find
3
5
8
()
(1.0328)(0.250)(30 10 m)
'2
.
5
8
1
0
s
3.00 10 m/s
sb
xx
t
c
γβ
−
−
×
∆=
=
=
×
×
where
'
'
'
bs
t
∆= −
.
(b) Since
∆
t'
is negative,
t
b
' is greater than
t
s
' . The small flash occurs first in
S'
.
17. (a) We take the flashbulbs to be at rest in frame
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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