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(e) Eq. 2
′
in Table 372 gives
()
( )
2
21
98
//
(2.00) 40.0 10
s (0.866)(20.0 m) /(2.998 10 m/s)
35.5 ns .
ttt
tv
x
c
t
x
c
γγ
β
−
′′′
∆= −= ∆−∆
= ∆−∆
⎡⎤
=×
−
×
⎣⎦
=−
In absolute value, the two events are separated by 35.5 ns.
(f) The negative sign obtained in part (e) implies event 2 occurred before event 1.
20. The timedilation information in the problem (particularly, the 15 s on “his
wristwatch… which takes 30.0 s according to you”) reveals Lorentz factor is
γ
= 2.00
(see Eq. 379), which implies his speed is
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

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