ch37-p040 - 40. From Eq. 28-37, we have Q = Mc 2 =...

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40. From Eq. 28-37, we have [ ] 22 3(4.00151u) 11.99671u (0.00782u)(931.5MeV/u) 7.28Mev. QM c c =−∆ =− Thus, it takes a minimum of 7.28 MeV supplied to the system to cause this reaction. We note that the masses given in this problem are strictly for the nuclei involved; they are not
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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