40. From Eq. 28-37, we have [ ]223(4.00151u) 11.99671u(0.00782u)(931.5MeV/u)7.28Mev.QMcc=−∆=−−Thus, it takes a minimum of 7.28 MeV supplied to the system to cause this reaction. We note that the masses given in this problem are strictly for the nuclei involved; they are not
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.