ch37-p046 - 46. (a) Using K = mec2 ( 1) (Eq. 37-52) and...

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we obtain 2 1.0000000keV 1 1 1.00195695 1.0019570. 510.9989keV e K mc γ =+ = + = (b) Therefore, the speed parameter is 22 11 1 1 0.062469542. (1.0019570) β =− = (c) For 1.0000000 MeV K = , we have 2 1.0000000MeV 1 1 2.956951375 2.9569514. 0.5109989MeV e K = + = (d) The corresponding speed parameter is 2 1 0.941079236 0.94107924. βγ = (e) For K = 1.0000000 GeV, we have
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