ch37-p048 - Presumably, a train would be required. (c) We...

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48. (a) From the information in the problem, we see that each kilogram of TNT releases (3.40 × 10 6 J/mol)/(0.227 kg/mol) = 1.50 × 10 7 J. Thus, (1.80 × 10 14 J)/(1.50 × 10 7 J/kg) = 1.20 × 10 7 kg of TNT are needed. This is equivalent to a weight of 1.2 × 10 8 N. (b) This is certainly more than can be carried in a backpack.
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Unformatted text preview: Presumably, a train would be required. (c) We have 0.00080 mc 2 = 1.80 10 14 J, and find m = 2.50 kg of fissionable material is needed. This is equivalent to a weight of about 25 N, or 5.5 pounds. (d) This can be carried in a backpack....
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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