This preview shows page 1. Sign up to view the full content.
This is the end of the preview. Sign up
to
access the rest of the document.
Unformatted text preview: 50. (a) We set Eq. 3752 equal to 2mc2, as required by the problem, and solve for the
speed. Thus,
⎛1
⎞
mc 2 ⎜
− 1⎟ = 2mc 2
⎜ 1− β 2
⎟
⎝
⎠
leads to β = 2 2 / 3 ≈ 0.943.
(b) We now set Eq. 3748 equal to 2mc2 and solve for the speed. In this case,
mc 2
1− β
leads to β = 3 / 2 ≈ 0.866. 2 = 2mc 2 ...
View
Full
Document
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics

Click to edit the document details