(c) Using mpc2= 938.272 MeV, the Lorentz factor is γ= 1 + 10.00 MeV/938.272 MeV = 1.01065 1.011≈. (d) The speed parameter is 210.1448440.1448.βγ−=−=≈(e) With mαc2= 3727.40 MeV, we obtain = 10.00/3727.4 + 1 = 1.002681.003≈. (f) The speed parameter is 210.07310370.07310−=≈. 54. From Eq. 37-52, = (K/mc
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.