ch37-p059

# ch37-p059 - 59. (a) Before looking at our solution to part...

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59. (a) Before looking at our solution to part (a) (which uses momentum conservation), it might be advisable to look at our solution (and accompanying remarks) for part (b) (where a very different approach is used). Since momentum is a vector, its conservation involves two equations (along the original direction of alpha particle motion, the x direction, as well as along the final proton direction of motion, the y direction). The problem states that all speeds are much less than the speed of light, which allows us to use the classical formulas for kinetic energy and momentum ( Km v = 1 2 2 and G G pm v = , respectively). Along the x and y axes, momentum conservation gives (for the components of G v oxy ): oxy oxy, oxy, oxy oxy oxy, oxy, oxy 4 17 1 0. 17 xx p yp p y p p m mv m v v v v m m m v v v v m α αα =⇒ = =+ = To complete these determinations, we need values (inferred from the kinetic energies given in the problem) for the initial speed of the alpha particle ( v ) and the final speed of the proton ( v p ). One way to do this is to rewrite the classical kinetic energy expression as

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## This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

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ch37-p059 - 59. (a) Before looking at our solution to part...

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