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Unformatted text preview: 61. (a) The spatial separation between the two bursts is vt. We project this length onto the
direction perpendicular to the light rays headed to Earth and obtain Dapp = vt sin θ.
(b) Burst 1 is emitted a time t ahead of burst 2. Also, burst 1 has to travel an extra
distance L more than burst 2 before reaching the Earth, where L = vt cos θ (see Fig. 3730); this requires an additional time t' = L/c. Thus, the apparent time is given by
Tapp = t − t ′ = t − LM FG IJ
N HK OP
Q vt cosθ
v
= t 1−
cosθ .
c
c (c) We obtain
Vapp = Dapp
Tapp = LM (v / c) sinθ OPc = LM (0.980) sin 30.0° OPc = 3.24 c.
N1 − (v / c) cosθ Q N1 − (0.980) cos30.0° Q ...
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Light

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