ch37-p069 - AD = 1 M AD 1 + M AD = 1 7 /18 1 7 /18 + = 11...

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Now, with β AB given as 1/5 (see problem statement), then M AB is seen to be 2/3 (which is (1 – 1/5) divided by (1 + 1/5) ). With BC = 2/5, we similarly find M BC = 7/3, and for CD = 3/5 we get M CD = 1/4 . Thus, M AD = M AB M BC M CD = 2 3 · 7 3 · 1 4 = 7 18 . Consequently,
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Unformatted text preview: AD = 1 M AD 1 + M AD = 1 7 /18 1 7 /18 + = 11 25 = 0.44. By the definition of the speed parameter, we obtain v AD = 0.44 c . 69. We note, for use later in the problem, that 1 1 1 1 M M M = = + +...
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