71. The strategy is to find the speed from E= 1533 MeV and mc2= 0.511 MeV (see Table 37-3) and from that find the time. From the energy relation (Eq. 37-48), we obtain 2220.511 MeV110.999999941533 MeVmcvccccE⎛⎞=−=≈⎜⎟⎝⎠so that we conclude it took the electron 26 y to reach us. In order to transform to its own “clock” it’s useful to compute γdirectly from Eq. 37-48: 21533 MeV30000.511 MeVEmc===though if one is careful one can also get this result from
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.