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71. The strategy is to find the speed from
E
= 1533 MeV and
mc
2
= 0.511 MeV (see
Table 373) and from that find the time. From the energy relation (Eq. 3748), we obtain
2
2
2
0.511 MeV
1
1
0.99999994
1533 MeV
mc
vc
c
cc
E
⎛⎞
=−
=
≈
⎜⎟
⎝⎠
so that we conclude it took the electron 26 y to reach us. In order to transform to its own
“clock” it’s useful to compute
γ
directly from Eq. 3748:
2
1533 MeV
3000
0.511 MeV
E
mc
==
=
though if one is careful one can also get this result from
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This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.
 Spring '08
 Any
 Physics, Energy

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