ch37-p071 - 71. The strategy is to find the speed from E =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
71. The strategy is to find the speed from E = 1533 MeV and mc 2 = 0.511 MeV (see Table 37-3) and from that find the time. From the energy relation (Eq. 37-48), we obtain 2 2 2 0.511 MeV 1 1 0.99999994 1533 MeV mc vc c cc E ⎛⎞ =− = ⎜⎟ ⎝⎠ so that we conclude it took the electron 26 y to reach us. In order to transform to its own “clock” it’s useful to compute γ directly from Eq. 37-48: 2 1533 MeV 3000 0.511 MeV E mc == = though if one is careful one can also get this result from
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online