ch38-p009 - 9. The total energy emitted by the bulb is E =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
9. The total energy emitted by the bulb is E = 0.93 Pt , where P = 60 W and t = 730 h = (730 h)(3600 s/h) = 2.628 × 10 6 s. The energy of each photon emitted is E ph = hc / λ . Therefore, the number of photons
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 06/03/2011 for the course PHY 2049 taught by Professor Any during the Spring '08 term at University of Florida.

Ask a homework question - tutors are online